How do you factor $3x^2-2$ ?

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Answer 1 · 2018-06-26T05:23:36

$3(x-sqrt(2/3))(x+sqrt(2/3))$

First divide by the number in front of $x^2$

$(3x^2-2)/(color(red)3) rarr x^2-2/3$

Solve for roots by setting equal to 0

$x^2-2/3=0 rarr x^2=2/3 rarr x=+-sqrt(2/3)$

Multiply by 3 and $(x-"root")$ such as

$3(x-sqrt(2/3))(x--sqrt(2/3)) rarr 3(x-sqrt(2/3))(x+sqrt(2/3))$

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