How do you factor $3x^2 + 5x + 1$ ?

Question

4845 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-15T17:06:10

not factorable

$y = 3x^2 + 5x + 1$
$D = b^2 - 4ac = 25 - 12 = 13.$
Since D is not a perfect square, this trinomial can not be factored

How do you factor 3x^2 + 5x + 13x^2 + 5x + 1?