How do you factor $3 x^{2} - 6 x$ $3x^2 - 6x$ ?

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How do you factor $3 x^{2} - 6 x$ $3x^2 - 6x$ ?

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Answer 1 · 2015-07-31T17:41:11

$3 x (x - 2)$ $3x(x-2)$

Explanation:

The term $3 x^{2}$ $3x^2$ can be thought of as $3 x \cdot x$ $3x*x$ and the term $6 x$ $6x$ can be thought of as $3 x \cdot 2$ $3x*2$ . The $3 x$ $3x$ is therefore a common factor that can be factored out (reversing the distributive property), and keeping the minus sign in place: $3 x^{2} - 6 x = 3 x (x - 2)$ $3x^2-6x=3x(x-2)$ .

This also implies that the roots ( $x$ $x$ -intercepts) of the function $f (x) = 3 x^{2} - 6 x = 3 x (x - 2)$ $f(x)=3x^2-6x=3x(x-2)$ are $x = 0$ $x=0$ and $x = 2$ $x=2$ .

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How do you factor $3 x^{2} - 6 x$ $3x^2 - 6x$ ?

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