How do you factor $3 x^{2} + 6 x - 9$ $3x^2+6x-9$ ?

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Answer 1 · 2015-09-24T21:23:05

Refer to explanation

We have that

$3x^2+6x-9=3*(x^2+2x+1)-9-3=3*(x+1)^2-12=(sqrt3*(x+1))^2-(sqrt12)^2=(sqrt3*(x+1)+2sqrt3)*(sqrt3*(x+1)-2sqrt3)=sqrt3*(x+3)*sqrt3(x-1)=3(x+3)(x-1)$

Finally

$3x^2+6x-9=3(x+3)(x-1)$

How do you factor 3x^2+6x-93x2+6x−93x^2+6x-9?