How do you factor $3 x^{2} + 7 x + 2$ $3x^2+7x+2$ ?

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Answer 1 · 2016-07-29T10:58:03

$3 x^{2} + 7 x + 2 = (3 x + 1) (x + 2)$ $3x^2+7x+2=(3x+1)(x+2)$

$3 x^{2} + 7 x + 2 = 3 x^{2} + 6 x + x + 2 = 3 x (x + 2) + 1 (x + 2) = (3 x + 1) (x + 2)$ $3x^2+7x+2= 3x^2+6x+x+2 = 3x(x+2)+1(x+2)=(3x+1)(x+2)$ [Ans]

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