How do you factor $3 x^{2} + 9 x - 12 = 0$ $3x^2 + 9x - 12 = 0$ ?

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How do you factor $3 x^{2} + 9 x - 12 = 0$ $3x^2 + 9x - 12 = 0$ ?

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Answer 1 · 2016-05-11T15:04:46

(x - 1)(3x + 12)

Explanation:

$y = 3 x^{2} + 9 x - 12$ $y = 3x^2 + 9x - 12$
Since a + b + c = 0, use shortcut.
The 2 factors are (x - 1) and $(x - \frac{c}{a} = x + \frac{12}{3})$ $(x - c/a = x + 12/3)$
$y = 3 (x - 1) (x + \frac{12}{3}) = (x - 1) (3 x + 12)$ $y = 3(x - 1)(x + 12/3) = (x - 1)(3x + 12)$

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How do you factor $3 x^{2} + 9 x - 12 = 0$ $3x^2 + 9x - 12 = 0$ ?

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