How do you factor 3x2y212xyz2+12z4?

1 Answer
Oct 20, 2015

3(xy2z2)2

Explanation:

Temporarily replace
XXXxy with a and
XXXz2 with b
so we have
XXX3a212ab+12b2

which factors as
XXX=3(a24ab+4b2

XXX=3(a2b)2

Restoring the values for a and b
XXX=3(xy2z2)