How do you factor $3x^3+19x^2+30x+8$ ?

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Answer 1 · 2015-05-25T17:41:13

Since f(-2) = 0, then one factor is (x + 2)

$f(x) = (x + 2) (3x^2 + 13x + 8)$

The trinomial in parentheses can't be factored because its D = 169 - 96 = 73 is not a perfect square.

How do you factor 3x^3+19x^2+30x+8 3x^3+19x^2+30x+8 ?