How do you factor $3 x^{3} + 2 x^{2} - 27 x - 18$ $3x^3 + 2x^2 - 27x - 18$ ?

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Answer 1 · 2016-07-02T09:20:58

$3 x^{3} + 2 x^{2} - 27 x - 18 = (x + 3) (x - 3) (3 x + 2)$ $3x^3+2x^2-27x-18=(x+3)(x-3)(3x+2)$

$3 x^{3} + 2 x^{2} - 27 x - 18$ $3x^3+2x^2-27x-18$

= $x^{2} (3 x + 2) - 9 (3 x + 2)$ $x^2(3x+2)-9(3x+2)$

= $(x^{2} - 9) (3 x + 2)$ $(x^2-9)(3x+2)$

= $(x^{2} - 3 x + 3 x - 9) (3 x + 2)$ $(x^2-3x+3x-9)(3x+2)$

= $(x (x - 3) + 3 (x - 3)) (3 x + 2)$ $(x(x-3)+3(x-3))(3x+2)$

= $(x + 3) (x - 3) (3 x + 2)$ $(x+3)(x-3)(3x+2)$

How do you factor 3x3+2x2−27x−183x^3 + 2x^2 - 27x - 18?