How do you factor $3 x^{3} y^{2} - 147 x$ $3x^3y^2-147x$ ?

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Answer 1 · 2016-05-13T05:28:11

$3 x (x \cdot y - 7) (x \cdot y + 7)$ $3x(x*y-7)(x*y+7)$

Take $3 x$ $3x$ as a common factor
$3 x (x^{2} \cdot y^{2} - 49)$ $3x (x^2*y^2-49)$
$3 x (x \cdot y - 7) (x \cdot y + 7)$ $3x(x*y-7)(x*y+7)$

How do you factor 3x3y2−147x3x^3y^2-147x?