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How do you factor #3x^3y^2-147x#?

↳Redirected from "How do you evaluate #sin^-1 (-sqrt3/2)#?"

1 Answer

May 13, 2016

#3x(x*y-7)(x*y+7)#

Explanation:

Take #3x# as a common factor
#3x (x^2*y^2-49)#
#3x(x*y-7)(x*y+7)#

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