How do you factor $3y^2 + 21y + 36$ ?

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Answer 1 · 2016-04-09T11:32:54

$=3(y^2+7y +12)$
$=3(y^2+4y+3y +12)$
$=3(y(y+4)+3(y +4))$
$=3(y+4)(y+3)$

Answer 2 · 2016-04-09T12:01:57

$(3y+9)(y+4)$

Factors of 36 $->$ {1 , 36}, {2 , 18}, {3 , 12}, {4, 9}

Factors of 3 $->$ {1 , 3}

I have already experimented with these and found that the combination is:

$3(y+3)(y+4)$

How do you factor 3y^2 + 21y + 363y^2 + 21y + 36?