How do you factor $3 y^{2} + y - 16$ $3y^2 +y -16$ ?

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Answer 1 · 2015-07-17T22:40:00

Factor f(y) = 3y^2 + y - 16
Answer: not factorable

f(y) = 3y^2 + y - 16

D = 1 + 192 = 193. D is not a perfect square, then this function can't be factored.

How do you factor 3y2+y−163y^2 +y -16?