How do you factor $3 y - 6 x + 4 x y - 2 y^{2}$ $3y - 6x + 4xy - 2y^2$ ?

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Answer 1 · 2018-03-25T13:58:34

$(- 2 y + 3) (y - 2 x)$ $(-2y+3)(y-2x)$

I can do grouping in pairs.

$- 2 y^{2} + 3 y + 4 x y - 6 x$ $-2y^2+3y+4xy-6x$
$y (- 2 y + 3) - 2 x (- 2 y + 3)$ $y(-2y+3)-2x(-2y+3)$
$(- 2 y + 3) (y - 2 x)$ $(-2y+3)(y-2x)$

How do you factor 3y - 6x + 4xy - 2y^23y−6x+4xy−2y23y - 6x + 4xy - 2y^2?