How do you factor $4 - 49 z^{2}$ $4-49z^2$ ?

Question

3160 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-27T17:28:33

$(2 + 7 z) (2 - 7 z)$ $(2+7z)(2-7z)$

The expression if the difference of two squares

$(a + b) (a - b) = a^{2} - a b + a b - b^{2} = a^{2} - b^{2}$ $(a+b)(a-b)=a^2-ab+ab-b^2=a^2-b^2$

In this case

$a = 2$ $a=2$ , $a^{2} = 4$ $a^2=4$

$b = 7 z$ $b=7z$ , $b^{2} = 49 z^{2}$ $b^2=49z^2$

How do you factor 4−49z24-49z^2?