How do you factor $4 (x^{2}) - 28 x + 49$ $4(x^2) - 28x + 49$ ?

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Answer 1 · 2018-03-29T00:24:39

${(2 x - 7)}^{2}$ $(2x - 7)^2$

It is a perfect square:
$4 x^{2} - 28 x + 49 = {(2 x - 7)}^{2}$ $4x^2 - 28x + 49 = (2x - 7)^2$

How do you factor 4(x2)−28x+494(x^2) - 28x + 49?