How do you factor $44+15h+h^2$ ?

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Answer 1 · 2017-01-26T15:24:53

See the entire process below:

First, rewrite this equation in standard binomial form:

$h^2 + 15h + 44$

Now "play" with different multiples of $44$ (1x44, 2x22, 4x11) which also add up to $15$ giving:

$(h + 4)(h + 11)$

How do you factor 44+15h+h^244+15h+h^2?