How do you factor $49x^2 -81$ ?

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Answer 1 · 2018-03-22T05:26:39

$(7x+9)(7x-9)$

Given -

$49x^2-81$

It is in the form $a^2-b^2$

Factors for the expression $a^2-b^2$ is $(a+b)(a-b)$

Following this, we can find the factors for the given expression $49x^2-81$

$(7x+9)(7x-9)$

How do you factor 49x^2 -81 49x^2 -81 ?