How do you factor $4 a^{2} + 20 a + 25$ $4a^2 + 20a + 25$ ?

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How do you factor $4 a^{2} + 20 a + 25$ $4a^2 + 20a + 25$ ?

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Answer 1 · 2015-06-26T18:19:18

It is a perfect square trinomial:
$4 a^{2} + 20 a + 25 = {(2 a + 5)}^{2}$ $4a^2+20a+25 = (2a+5)^2$

Explanation:

The first term is the square of $2 a$ $2a$

The last term is the square of $5$ $5$

Multiplt those two, then doubles the number. Is that the middle term? If yes, then it is a perfect square.

$2 a \times 5 = 10 a$ $2a xx 5 = 10a$ . Now double that (multiply by $2$ $2$ ): $2 \times 10 a = 20 a$ $2 xx 10a = 20a$ Yes, that is the middle term on the original expression, so it is a perfect square,

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How do you factor $4 a^{2} + 20 a + 25$ $4a^2 + 20a + 25$ ?

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