How do you factor $4a^3 + 4a^2 - 48a$ ?

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Answer 1 · 2016-04-14T15:38:54

$4a^3+4a^2-48a=4a(a+4)(a-3)$

$4a^3+4a^2-48a=4a(a^2+a-12)$

$a^2+a-12=(a+4)(a-3)$

$4a^3+4a^2-48a=4a(a+4)(a-3)$

How do you factor 4a^3 + 4a^2 - 48a4a^3 + 4a^2 - 48a?