How do you factor $4 m^{2} - 28 m n + 49 n^{2}$ $4m^2-28mn+49n^2$ ?

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Answer 1 · 2018-03-22T03:51:52

${(2 m - 7 n)}^{2}$ $(2m - 7n)^2$

This is a perfect square -->
${(2 m - 7 n)}^{2} = 4 m^{2} - 28 m n + 49 n^{2}$ $(2m - 7n)^2 = 4m^2 - 28mn + 49n^2$

How do you factor 4m2−28mn+49n24m^2-28mn+49n^2?