How do you factor $4 n^{2} - 49$ $4n^2-49$ ?

Question

4797 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-03T06:35:17

$4 n^{2} - 49 = {(2 n)}^{2} - 7^{2} = (2 n - 7) (2 n + 7)$ $4n^2-49 = (2n)^2-7^2 = (2n-7)(2n+7)$

...using the difference of squares identity:

$a^{2} - b^{2} = (a - b) (a + b)$ $a^2-b^2 = (a-b)(a+b)$

How do you factor 4n^2-494n2−494n^2-49?