How do you factor 4n^2 + 68n + 250 ?

1 Answer
Nghi N.
Oct 10, 2015

Factor f(n) = 4n^2 + 68n + 250

Explanation:

f(n) = 2y = 2(2n^2 + 34n + 125).
Factor y = 2n^2 + 34n + 125
D = b^2 - 4ac = 1156 - 4000 = -2844 < 0. Since its D < 0, this trinomial y can't be factored.
Finally, f(n) = 2(2n^2 + 34n + 125)

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