How do you factor $4p^2q+pq^2+4p^3$ by grouping?

Question

1384 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-21T17:45:44

$4p^2q+pq^2+4p^3=p(q+2p)(q+2p)$

Separate out the common factor $p$ , rearrange into descending powers of $q$ then recognise the perfect square trinomial:

$4p^2q+pq^2+4p^3$

$=p(4pq+q^2+4p^2)$

$=p(q^2+4pq+4p^2)$

$=p(q+2p)(q+2p)$

How do you factor 4p^2q+pq^2+4p^34p^2q+pq^2+4p^3 by grouping?