How do you factor $4t^3-64t^2-128t$ ?

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Answer 1 · 2016-08-30T11:43:04

$4t(t-8+4sqrt6)(t-8-4sqrt6)$

$4t^3-64t^2-128t=4t(t^2-16t-32)=4t((t-8)^2-64-32)=4t((t-8)^2-96) =4t((t-8)^2-(4sqrt6)^2)=4t((t-8+4sqrt6)(t-8-4sqrt6))$ [Ans]

How do you factor 4t^3-64t^2-128t4t^3-64t^2-128t?