How do you factor $4x^2-10x+6$ ?

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Answer 1 · 2018-06-15T14:51:19

$2(x-1)(2x-3)$

First factor out the GCF by the distributive property:

$4x^2-10x+6$

$2(2x^2-5x+3)$

Now the factors have to have a sum $-5$ and a product $2*3=6$

-2, -3 will work

Now factor by grouping, replace the $-5x$ with $-2x-3x$

$2(2x^2-5x+3)$

$2(2x^2-2x-3x+3)$

$2(2x(x-1)-3(x-1))$

now factor out $(x-1)$

$2(x-1)(2x-3)$

How do you factor 4x^2-10x+64x^2-10x+6?