How do you factor $- 4 x^{2} + 11 x + 20$ $-4x^2 +11x + 20$ ?

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Answer 1 · 2016-08-28T19:23:06

$- (x - 4) (4 x + 5)$ $-(x-4)(4x+5)$ .

Let $P (x) = - 4 x^{2} + 11 x + 20$ $P(x)=-4x^2+11x+20$ .

We have, $4 \times 20 = 4 \times 4 \times 5 = 16 \times 5, & 16 - 5 = 11$ $4xx20=4xx4xx5=16xx5, & 16-5=11$ . Therefore,

$P(x)=ul(-4x^2+16x)-ul(5x+20)$

$=-4x(x-4)-5(x-4)$

$=(x-4)(-4x-5)$

$=-(x-4)(4x+5)$ .

How do you factor -4x^2 +11x + 20−4x2+11x+20-4x^2 +11x + 20?