How do you factor $- 4 x^{2} - 23 x + 6$ $-4x^2 - 23x + 6$ ?

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How do you factor $- 4 x^{2} - 23 x + 6$ $-4x^2 - 23x + 6$ ?

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Answer 1 · 2018-03-22T19:51:01

$(4 x - 1) (x + 6)$ $(4x-1)(x+6)$

Explanation:

$- 4 x^{2} - 23 x + 6 = 4 x^{2} + 23 - 6$ $-4x^2-23x+6 = 4x^2+23-6$
$4 x^{2} + 24 x - x - 6 = 4 x (x + 6) - 1 (x + 6)$ $4x^2+24x-x-6 = 4x(x+6)-1(x+6)$ therefore: $(4 x - 1) (x + 6)$ $(4x-1)(x+6)$

$x = - 6 or + 1$ $x= -6 or +1$

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How do you factor $- 4 x^{2} - 23 x + 6$ $-4x^2 - 23x + 6$ ?

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How do you factor $- 4 x^{2} - 23 x + 6$ $-4x^2 - 23x + 6$ ?