How do you factor $4 x^{2} - 24 x + 32$ $4x^2 - 24x + 32$ ?

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How do you factor $4 x^{2} - 24 x + 32$ $4x^2 - 24x + 32$ ?

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Answer 1 · 2015-05-23T21:45:45

$4 x^{2} - 24 x + 32 = 4 (x^{2} - 6 x + 8)$ $4x^2-24x+32 = 4(x^2-6x+8)$

$= 4 (x^{2} - (2 + 4) x + (2 \times 4))$ $= 4(x^2-(2+4)x+(2xx4))$

$= 4 (x - 2) (x - 4)$ $= 4(x-2)(x-4)$

The method by which $(x^{2} - 6 x + 8)$ $(x^2-6x+8)$ is factored is sometimes called "Splitting the middle" - finding two numbers whose sum is the middle coefficient and whose product is the constant term.

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How do you factor $4 x^{2} - 24 x + 32$ $4x^2 - 24x + 32$ ?

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