How do you factor $4x^2 + 24x + 36$ ?

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Answer 1 · 2018-03-08T00:15:12

$4(x+3)(x+3)$

First, factor out four from each of the elements:

$4(x^2+6x+9)$

Then find factors of the last and first elements that when added make the middle one:

$3 times 3 = 9" "$ and $" "3+3 = 6$

$=>4(x^2+3x+3x+9)$

$=>4(x(x+3)+3(x+3))$

$=>4(x+3)(x+3)$

How do you factor 4x^2 + 24x + 364x^2 + 24x + 36?