How do you factor 4x^2+38x+34=0 ?

1 Answer
Nghi N.
Dec 17, 2015

Factor f(x) = 4x^2 + 38x + 34 = 0

Ans: f(x) = 2(x + 1)(2x + 17)

Explanation:

f(x) = 2y = 2(2x^2 + 19x + 17) = 0. Factor y.
Since (a - b + c = 0) use the shortcut. The 2 real roots are: -1 and -c/a = -17/2. The 2 factors are: (x + 1) and (x + 17/2)
Factored form f(x) = 2(x + 1)(2x + 17)

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