How do you factor $4 x^{2} + 5 x y + 16 x + 20 y$ $4x^2 + 5xy + 16x + 20y$ ?

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Answer 1 · 2015-05-23T23:59:32

4-term polynomials like this need to be factored first as two binomials.

$4 x^{2} + 5 x y + 16 x + 20 y$ $4x^2 + 5xy + 16x + 20y$

$(4 x^{2} + 5 x y) + (16 x + 20 y)$ $(4x^2 + 5xy) + (16x + 20y)$

'X' can be factored from the left side and 4 can be factored from the right side.

$x (4 x + 5 y) + 4 (4 x + 5 y)$ $x(4x+5y) + 4(4x+5y)$

According to the converse of the distributive property, I can combine these two terms.

$(x + 4) (4 x + 5 y)$ $(x+4)(4x+5y)$

Final Answer

How do you factor 4x2+5xy+16x+20y4x^2 + 5xy + 16x + 20y?