How do you factor $4 x^{3} + 16 x^{2} + x + 4$ $4x^3+16x^2+x+4$ ?

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Answer 1 · 2018-04-03T11:21:20

$(x + 4) (4 x^{2} + 1)$ $(x+4)(4x^2+1)$

$4 x^{3} + 16 x^{2} + x + 4$ $4x^3+16x^2+x+4$
= $4 x^{2} (x + 4) + (x + 4)$ $4x^2(x+4)+(x+4)$
= $(x + 4) (4 x^{2} + 1)$ $(x+4)(4x^2+1)$

How do you factor 4x3+16x2+x+44x^3+16x^2+x+4?