How do you factor $4 x^{3} - 32 = 0$ $4x^3 - 32= 0$ ?

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Answer 1 · 2018-05-03T03:56:45

$x = 2$ $x = 2$

$4 x^{3} - 32 = 0$ $4x^3 - 32 = 0$

Factor out the $4$ $4$ :
$4 (x^{3} - 8) = 0$ $4(x^3 - 8) = 0$

Divide both sides by $4$ $color(blue)4$ :
$\frac{4 (x^{3} - 8)}{4} = \frac{0}{4}$ $(4(x^3 - 8))/color(blue)4 = 0/color(blue)4$

$x^{3} - 8 = 0$ $x^3 - 8 = 0$

Add $8$ $color(blue)8$ to both sides of the equation:
$x^3 - 8 quadcolor(blue)(+quad8) = 0 quadcolor(blue)(+quad8)$

$x^3 = 8$

Take the cube root of both sides:
$root(3)(x^3) = root(3)(8)$

$x = 2$

Hope this helps!

How do you factor 4x^3 - 32= 04x3−32=04x^3 - 32= 0?