How do you factor $4x^3-8x^2-12x$ ?

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Answer 1 · 2016-02-17T09:03:40

$4x(x+1)(x-3)$

Since all terms contain at least one $x$ and a multiple of $4$ , the GCF $4x$ , which can be factored out.

Rewrite the trinomial.

$4x(x^2-2x-3)$

Factor the trinomial. Find two numbers that when added equal $-2$ and when multiplied equal $-3$ . The numbers $1$ and $-3$ fit the requirements.

Rewrite the trinomial in its factored form.

$4x(x+1)(x-3)$

How do you factor 4x^3-8x^2-12x4x^3-8x^2-12x?