How do you factor $4y² +11y-3$ ?

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Answer 1 · 2015-08-09T20:15:05

$(4y-1)(y+3)$

Note 3 is a prime number so only has factors 3 and 1. 4 can have factors 2 and 2 or 4 and 1, therefore the factorisation will likely be of the form:

$(2y+-3)(2y+-1)$

or

$(4y+-(3,1))(y+-(3,1))$

In the second case by inspection we see that:

$4y^2+11y-3=(4y-1)(y+3)$

How do you factor 4y² +11y-34y² +11y-3?