How do you factor ${(4 y - 5)}^{2} + 3 (4 y - 5) - 70$ $(4y-5)^2+3(4y-5)-70$ ?

Question

How do you factor ${(4 y - 5)}^{2} + 3 (4 y - 5) - 70$ $(4y-5)^2+3(4y-5)-70$ ?

1 Answer

Impact of this question

1992 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-13T01:15:51

This can be factored as $4 (4 y + 5) (y - 3)$ $4(4y +5)(y - 3)$

Explanation:

We let $a = 4 y - 5$ $a = 4y - 5$ . Then the polynomial can be rewritten as:

$= a^{2} + 3 a - 70$ $=a^2 + 3a - 70$

Which is a standard polynomial of the form $a x^{2} + b x + c$ $ax^2 + bx + c$ . We find two numbers that multiply to $c$ $c$ and that add to $b$ $b$ . These would be $+ 10$ $+10$ and $- 7$ $-7$ .

$= (a + 10) (a - 7)$ $=(a + 10)(a - 7)$

Resubstitute to get:

$= (4 y - 5 + 10) (4 y - 5 - 7)$ $=(4y - 5 + 10)(4y - 5 - 7)$

$= (4 y + 5) (4 y - 12)$ $= (4y + 5)(4y - 12)$

$= 4 (4 y + 5) (y - 3)$ $=4(4y + 5)(y - 3)$

Hopefully this helps!

Science

Math

Humanities

... and beyond

How do you factor ${(4 y - 5)}^{2} + 3 (4 y - 5) - 70$ $(4y-5)^2+3(4y-5)-70$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor (4y−5)2+3(4y−5)−70(4y-5)^2+3(4y-5)-70?

1 Answer

Explanation:

Related questions

Impact of this question

How do you factor ${(4 y - 5)}^{2} + 3 (4 y - 5) - 70$ $(4y-5)^2+3(4y-5)-70$ ?