How do you factor $54a^4 - 16ab^3$ ?

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Answer 1 · 2016-07-05T00:10:33

$2a(3a−2b)(9a^2+6ab+4b^2)$

Take out common factors from $54$ and $16$ .
The highest value that can be factored out is $2$ .

So far:

$2(27a^4 - 8ab^3)$

Now lets take out common factors between the variables. The highest value that can be pulled out from $a^4$ and $ab^3$ is $a$ .

$2a(27a^3 - 8b^3$ )

We're not done yet.

$2a(3a−2b)(9a^2+6ab+4b^2)$

How do you factor 54a^4 - 16ab^354a^4 - 16ab^3?