How do you factor 54c^3d^4+9c^4d^254c3d4+9c4d2?

2 Answers
Jun 16, 2018

9c^3d^2(6d^2+c)9c3d2(6d2+c)

Explanation:

We check it by expanding:
9c^3d^2(6d^2+c)=54c^3d^4+9c^4d^29c3d2(6d2+c)=54c3d4+9c4d2

Aug 9, 2018

9c^3d^2(6d^2+c)9c3d2(6d2+c)

Explanation:

Look at what power each cc and dd is raised to and take out the most that you can out of both of them:

there are at least three c's in both terms so you can pull out a c^3c3 and there are at least 2 d's in both terms so pull out d^2d2. Finally there is a common factor 9 in both terms so we'll pull that out as well:

9c^3d^2(6d^2+c)9c3d2(6d2+c)