How do you factor $54 x^{4} - 2 x y^{6}$ $54x^4-2xy^6$ ?

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How do you factor $54 x^{4} - 2 x y^{6}$ $54x^4-2xy^6$ ?

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Answer 1 · 2015-10-27T18:46:44

$2 x (3 x - y^{2}) (9 x^{2} + 3 x y^{2} + y^{4})$ $2x(3x-y^2)(9x^2+3xy^2+y^4)$

Explanation:

$54 x^{4} - 2 x y^{6} = 2 x (27 x^{3} - y^{6})$ $54x^4-2xy^6= 2x(27x^3-y^6)$
$= 2 x ({(3 x)}^{3} - {(y^{2})}^{3}) = 2 x (3 x - y^{2}) (9 x^{2} + 3 x y^{2} + y^{4})$ $=2x((3x)^3-(y^2)^3)= 2x(3x-y^2)(9x^2+3xy^2+y^4)$

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How do you factor $54 x^{4} - 2 x y^{6}$ $54x^4-2xy^6$ ?

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