How do you factor $5a^3-a^2-5a+1$ ?

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Answer 1 · 2016-04-02T11:56:13

$(5a-1)(a+1)(a-1)$

$5a^3-a^2-5a+1 = 5a^3-5a^2+4a^2-4a-a+1=5a^2(a-1)+4a(a-1)-1(a-1) =(5a^2+4a-1)(a-1)= (5a^2+5a-a-1)(a-1)={5a(a+1)-1(a+1)}(a-1) =(5a-1)(a+1)(a-1)$ [Ans]

Answer 2 · 2016-04-02T12:08:43

$=5a(a^2-1)-1(a^2-1)$
$=(a^2-1)(5a-1)=(a+1)(a-1)(5a-1)$

How do you factor 5a^3-a^2-5a+15a^3-a^2-5a+1?