How do you factor $5 w^{2} + 2 w - 3$ $5w^2+2w-3$ ?

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Answer 1 · 2017-07-28T11:08:55

$5 (w + 1) (w - 0.6)$ $5(w+1)(w-0.6)$

$5 w^{2} + 2 w - 3 = 5 w^{2} + 5 w - 3 w - 3$ $5w^2 +2w -3 = 5w^2 +5w -3w -3$

$= 5 w (w + 1) - 3 (w + 1) = (w + 1) (5 w - 3)$ $= 5w(w+1) - 3(w +1) = (w+1)(5w-3)$

$= 5 (w + 1) (w - 0.6)$ $=5(w+1)(w-0.6)$ [Ans]

How do you factor 5w^2+2w-35w2+2w−35w^2+2w-3?