How do you factor $5 w^{2} + 7 w - 6$ $5w^2+7w-6$ ?

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Answer 1 · 2018-03-12T19:52:55

$(w + 2) (5 w - 3)$ $(w+2)(5w-3)$

Write as a sum or difference

$5 w^{2} + 10 w - 3 w - 6$ $5w^2+10w-3w-6$

Factor out $5 w$ $5w$ and $- 3$ $-3$ from the expression

$5 w (w + 2) - 3 (w + 2)$ $5w(w+2)-3(w+2)$

Factor out $w + 2$ $w+2$ from the expression

$(w + 2) (5 w - 3)$ $(w+2)(5w-3)$

How do you factor 5w^2+7w-65w2+7w−65w^2+7w-6?