How do you factor 5x^2-33x-14 5x2−33x−14?
1 Answer
Aug 10, 2015
Factor: y = 5x^2 - 33x - 14.
Ans: (5x + 2)(x - 7)
Explanation:
I use the new AC Method. y = 5(x + p)(x + q).
Converted trinomial: y' = 5x^2 - 33x - 70.
Factor pairs of (-70) --> (-2, 35). This sum is 33 = -b. Change this sum to the opposite.
Then p' = 2 and q' = -35.
Therefor p = 2/5 and q = -35/5 = -7
y = 5(x + 2/5)(x - 7) = (5x + 2)(x - 7)
