How do you factor $5 x^{2} - 5 y^{2} + m x^{2} - m y^{2}$ $5x^2-5y^2+mx^2-my^2$ ?

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Answer 1 · 2015-07-10T01:55:20

The answer is $(5 + m) (x + y) (x - y)$ $(5+m)(x+y)(x-y)$ .

$5 x^{2} - 5 y^{2} + m x^{2} - m y^{2}$ $5x^2-5y^2+mx^2-my^2$

Group the first two and last two terms together.

$(5 x^{2} - 5 y^{2}) + (m x^{2} - m y^{2})$ $(5x^2-5y^2)+(mx^2-my^2)$

Factor out the GCF for each group.

$5 (x^{2} - y^{2}) + m (x^{2} - y^{2})$ $5(x^2-y^2)+m(x^2-y^2)$

$x^{2} - y^{2} = (x + y) (x - y)$ $x^2-y^2=(x+y)(x-y)$

$5 (x + y) (x - y) + m (x + y) (x - y)$ $5(x+y)(x-y)+m(x+y)(x-y)$

Factor out the $(x + y) (x - y)$ $(x+y)(x-y)$ .

$(5 + m) (x + y) (x - y)$ $(5+m)(x+y)(x-y)$

How do you factor 5x^2-5y^2+mx^2-my^25x2−5y2+mx2−my25x^2-5y^2+mx^2-my^2?