How do you factor $5x^3+4x^2-10x-8$ by grouping?

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Answer 1 · 2016-09-07T14:03:32

$(x^2-2)(5x+4)$

Let $p(x)=5x^3+4x^2-10x-8$

$=ul(5x^3-10x)+ul(4x^2-8)$

$=5x(x^2-2)+4(x^2-2)$

$=(x^2-2)(5x+4)$

How do you factor 5x^3+4x^2-10x-8 5x^3+4x^2-10x-8 by grouping?