How do you factor $-62x^5 y^2 + 124x^4 y^3$ ?

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Answer 1 · 2016-05-09T19:33:46

$-62x^5y^2+124x^4y^3 = 62x^4y^2(2y-x)$

Both terms are divisible by $62$ , $x^4$ and $y^2$ , so divisible by $62x^4y^2$ :

$-62x^5y^2+124x^4y^3=62x^4y^2(-x+2y) = 62x^4y^2(2y-x)$

How do you factor -62x^5 y^2 + 124x^4 y^3-62x^5 y^2 + 124x^4 y^3?