How do you factor $64 y^{2} + 80 y + 25$ $64y^2 + 80y + 25$ ?

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How do you factor $64 y^{2} + 80 y + 25$ $64y^2 + 80y + 25$ ?

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Answer 1 · 2016-05-06T11:10:51

${(8 y + 5)}^{2}$ $(8y+5)^2$

Explanation:

$64 y^{2} + 80 y + 25 = 64 y^{2} + 40 y + 40 y + 25 = 8 y (8 y + 5) + 5 (8 y + 5) = (8 y + 5) (8 y + 5) = {(8 y + 5)}^{2}$ $64y^2+80y+25= 64y^2+40y+40y+25=8y(8y+5)+5(8y+5)=(8y+5)(8y+5)=(8y+5)^2$ [Ans]

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How do you factor $64 y^{2} + 80 y + 25$ $64y^2 + 80y + 25$ ?

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How do you factor 64y2+80y+2564y^2 + 80y + 25?

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How do you factor $64 y^{2} + 80 y + 25$ $64y^2 + 80y + 25$ ?