How do you factor $6 f^{3} - 8 f^{2} + 20 - 15 f$ $6f^3-8f^2+20-15f$ ?

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Answer 1 · 2015-05-02T04:47:55

$6 f^{3} - 8 f^{2} + 20 - 15 f$ $6f^3-8f^2+20-15f$

We make groups of 2 terms first

$= (6 f^{3} - 8 f^{2}) - (15 f - 20)$ $= (6f^3-8f^2)-(15f-20)$

Next, we factor out common terms from each group

$= 2 f^{2} (3 f - 4) - 5 (3 f - 4)$ $= 2f^2(3f-4) - 5(3f-4)$

The factor $3 f - 4$ $3f-4$ is common to each of the terms above

$= (3 f - 4) (2 f^{2} - 5)$ $= color(green)((3f - 4)(2f^2 - 5)$

How do you factor 6f3−8f2+20−15f6f^3-8f^2+20-15f?