How do you factor $6g^2 + 11g - 35$ ?

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Answer 1 · 2015-09-28T17:00:12

$(2g+7)(3g-5)$

By splitting the middle term 11g as 21g- 10g, this can be factorised as follows:

$6g^2 +21g-10g -35=0$

#3g(2g+7)-5(2g+7)=0

$(2g+7)(3g-5)$

How do you factor 6g^2 + 11g - 35 6g^2 + 11g - 35 ?