How do you factor $6p^2+5p-6$ ?

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Answer 1 · 2016-05-10T20:51:10

$6p^2+5p-6=(3p-2)(2p+3)$

Use an AC method:

Find a pair of factors of $AC = 6*6 = 36$ which differ by $B=5$

The pair $9, 4$ works, in that $9xx4=36$ and $9-4=5$ .

Use this pair to split the middle term and factor by grouping:

$6p^2+5p-6$

$=6p^2+9p-4p-6$

$=(6p^2+9p)-(4p+6)$

$=3p(2p+3)-2(2p+3)$

$=(3p-2)(2p+3)$

How do you factor 6p^2+5p-66p^2+5p-6?